t=t^2+11t+28

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Solution for t=t^2+11t+28 equation: 



t=t^2+11t+28

We move all terms to the left:

t-(t^2+11t+28)=0

We get rid of parentheses

-t^2+t-11t-28=0

We add all the numbers together, and all the variables

-1t^2-10t-28=0

a = -1; b = -10; c = -28;
Δ = b2-4ac
Δ = -102-4·(-1)·(-28)
Δ = -12
Delta is less than zero, so there is no solution for the equation

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